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A Solution of the P versus NP Problem?

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201–210 of 303 posts

Re: A Solution of the P versus NP Problem?

#201
post #194

If established researcher in the field makes a breakthrough of this magnitude I would expect rumors to start to circulating first. Showing the draft to few colleagues to see if they can spot mistakes before 'shaking the world' is probably a good idea.

Hmmm, maybe he analyzed the game theory:

If he publishes without consulting peers:

  If his proof is correct, he gets unending fame, millions in prize money.

  If his proof is laughably flawed, he'll promptly be forgotten as one of the 100s who have been wrong before him.
If he consults his peers:

  If his proof is correct, he may end up sharing credit, maybe they'll even publish his work quietly under their own name while he's still waiting for feedback. Maybe that is what we are reading now.

  If his proof is laughably flawed, then they'll give him his feedback and only his peers, instead of the whole internet will laugh at him for a day, before it's all forgotten.
Seems like with any tiny chance of a correct proof, the dominant strategy is, by far, to publish without consulting your peers.

Re: A Solution of the P versus NP Problem?

#202
post #29

This is definitely one of those "I'm going to wait for the peer review" claims, but it is pretty exciting. Pros: The author is not a dilettante, and is actively researching in the area ( http://theory.cs.uni-bonn.de/blum/Forschung/forsch.var ) Cons: It's not my area, but I was expecting something a little more novel for a solution to P?NP. This almost seems too simple (it might almost fit in a margin...). Could be pr…

> However, Andrew Wiles...

Grigori Perelman also comes to mind.

Re: A Solution of the P versus NP Problem?

#203
post #144

Earlier quoted context omitted.

I want to add another important aspect, the aspect of NP completeness. There is a bunch of problems considered "NP complete" and they are all related such that it is easy to translate one problem into another (easy as in "quickly"). This means, first: If P == NP, then all of these problems become easy, and second: if P == NP and we find an algorithm that solves only one of the NP complete problems quickly, then this…

NP completeness kinda works around the uncertainty of PxNP (with x ∈ {⊆, ⊊}), because it defines some sort of "weak subset" of NP comprised of "pretty sure these problems are not in P[, because no one yet thought of a polynomial reduction to a problem in P]". The last part in brackets is the catch here; if we could show that it is not possible, then P!=NP would immediately follow, and NP completeness would become a l…

NP completeness would still be of interest for particular algorithms because it would prove that those problems could not be solved in polynomial time. For instance, if factoring was shown to be NP complete, that would be a really useful result both for showing the security of algorithms like RSA as well as potentially disproving the extended Church-Turing thesis if quantum computers can be created.

Re: A Solution of the P versus NP Problem?

#205
post #175

Earlier quoted context omitted.

Even experienced people can make "silly" mistakes. https://arxiv.org/abs/1612.04208v1

They can —but that doesn't mean we should assume it's a silly mistake (as opposed to a deep one) without more information than that he's an accomplished researcher.

To add to this, I have a Ph.D. in applied mathematics. I am also an accomplished researcher, albeit retired.

I make more mistakes by 09:00 than most people will make all day. Hell, my girlfriend would suggest that we can move that time forward a couple of hours.

Re: A Solution of the P versus NP Problem?

#206
post #59

I like the straightforward title. I know that it is politically correct to christen your paper solving e.g. the Poincare conjecture like e.g. "Ricci flow with surgery on three-manifolds", but all rules are there to be broken once. I wish the author best of luck.

At least he couldn't resist making the important point a corollary.

what else, a mere remark? a theorem?

Re: A Solution of the P versus NP Problem?

#209
post #189

Earlier quoted context omitted.

A simple but wrong proof of "P = NP" is easier to write in some ways, since you "just" need to provide a single algorithm for one NP-hard problem, and show that it runs in polynomial time. It looks like many or most of the proof attempts in that list take this form. A plausible proof of "P != NP" won't be quite as simple to express, since it needs to prove that all such algorithms do not run in polynomial time.

Well yes! Two things: You have a successful algorithm that runs in P time that solves an NP Hard problem and 2) you can map other NP Hard problems to your problem. Without the second factor, it is only a demonstration of a "range" in the computational realm in question, where p = np or whatever the declaration. Being able to show that your pizza slice is actually an ocean of pizza, and also show that any other shape…

Your 2 is the easy part: "NP-hard" is exactly the set of problems to which any NP problems can be reduced in polynomial time, and there are many known existing examples, both within NP (aka NP-complete) and outside it.

Re: A Solution of the P versus NP Problem?

#210
post #99
post #56

Earlier quoted context omitted.

I think it's even less useful, even if P = NP it is possible that no one finds an algorithm. Creating a (useful) algorithm is independent of proving the theorem. Also interesting is that someone could create an algorithm that solves NP complete in polynomial time without proving P=NP. They would be unable to prove the algorithm correct though.

Alternately, a polynomial time algorithm is specified and the exponent is, say, 2500. Mathematically huge, practically useless.

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