Heyyy man, what if the universe is LINEAR?
I realized that derivatives are linear
21–30 of 76 posts
Re: I realized that derivatives are linear
#22This is why you take linear algebra and calculus before doing machine learning.
Re: I realized that derivatives are linear
#23Well this is the whole point of derivatives (i.e. tangent maps): to be linear approximations of functions. So yes, a linear approximation of a linear function is the function itself.
If a function f passes through some point (a,b), then the tangent to f through that point is given by (y-b) = f'(a)·(x-a) and that function is affine but usually not linear. (For the tangent curve to be a linear function, you would need a·f'(a) = b, so that the tangent goes through the point (0,0).) It's not at all obvious to me that this means that the function d(f) = df/dx is linear. It is linear, but I don't see h…
Re: I realized that derivatives are linear
#24Well this is the whole point of derivatives (i.e. tangent maps): to be linear approximations of functions. So yes, a linear approximation of a linear function is the function itself.
Re: I realized that derivatives are linear
#25Earlier quoted context omitted.
You are right, but what you are saying has nothing to do with the author's point: what he is saying is that the differentiation operator itself is linear, which is a meaningful and true fact even in spaces where you have no idea of what a linear function is.
I think you'll find that derivatives are overwhelming defined as operators on vector spaces. It is definitely correct to talk about a linear function on a vector space.
Re: I realized that derivatives are linear
#26Re: I realized that derivatives are linear
#27Earlier quoted context omitted.
I think you'll find that derivatives are overwhelming defined as operators on vector spaces. It is definitely correct to talk about a linear function on a vector space.
I agree with you, but this is not what GGP is saying. GGP is saying another true fact (i.e., that derivative of a linear function is that same function), which a different thing than stating, as the article says, that the differentiation operator is linear. On a manifold there is no concept of a linear function, so you cannot say that the derivative of a linear function is the same function, but the differentiation o…
Re: I realized that derivatives are linear
#28Earlier quoted context omitted.
I think you'll find that derivatives are overwhelming defined as operators on vector spaces. It is definitely correct to talk about a linear function on a vector space.
I agree with you, but this is not what GGP is saying. GGP is saying another true fact (i.e., that derivative of a linear function is that same function), which a different thing than stating, as the article says, that the differentiation operator is linear. On a manifold there is no concept of a linear function, so you cannot say that the derivative of a linear function is the same function, but the differentiation o…
In any case, it is probably a good thing to get a good intuition of what differentiation and derivatives are in the vector space setting before digging into differential geometry.
Re: I realized that derivatives are linear
#29This is why you take linear algebra and calculus before doing machine learning.
The dude/dudette figured it out on their own which is what math is actually about. Who cares if it's well known? Knowing a fact because you learned it in a class is cool and all but it's not the only way to acquire knowledge, and I would argue not even the best way---just the most efficient fact/hour ratio.
Re: I realized that derivatives are linear
#30Well this is the whole point of derivatives (i.e. tangent maps): to be linear approximations of functions. So yes, a linear approximation of a linear function is the function itself.
If a function f passes through some point (a,b), then the tangent to f through that point is given by (y-b) = f'(a)·(x-a) and that function is affine but usually not linear. (For the tangent curve to be a linear function, you would need a·f'(a) = b, so that the tangent goes through the point (0,0).) It's not at all obvious to me that this means that the function d(f) = df/dx is linear. It is linear, but I don't see h…
From this you obtain that the derivative of any linear combination is the linear combination of the derivatives: differentiation is linear.