Earlier quoted context omitted.
> I have an execution environment, Wasm, where doing this is pretty well defined, in fact. So if I want to read the memory at address 12345, which is within bounds of the linear memory (and there's a builtin to make sure), why should it be undefined behavior? How would you define it? Especially in a way that is consistent with the rest of the language and allows common optimizations (remember that C supports variable…
Just read whatever is at address 12345 of the linear memory. Doesn't matter what that is. If it's an object, if it was malloc'ed, if it's the "C stack", a "global". It's the only way to interpret *(uint64_t*)(12345) when the standard says that a integer-to-pointer conversion is "intended to be consistent with the addressing structure of the execution environment" . There exists an instruction to do that load in Wasm,…
For what it’s worth there’s a reason you’re supposed to do this kind of access through memcpy, not by dereferencing made up pointers.
> There exists an instruction to do that load in Wasm, there's a builtin to check that 12345 points to addressable memory, the load is valid at the assembly level, the standard says the implementation should define this to be consistent with the addressing structure of the execution environment, why the heck are we playing games and allowing the compiler to say, "nope, that's not valid, so your entire program is invalid, and we can do what ever we want, no diagnostic required"?
Because the language standard is defined to target a virtual machine as output, not any given implementation. That virtual machine is then implemented on various platforms, but the capabilities of the underlying system aren’t directly accessible - they are only there to implement the C virtual machine. That’s why C can target so many different target machines.