Earlier quoted context omitted.
If you look at the Wikipedia page for second order arithmetic, there is a definition in the language of first order logic as a two-sorted theory comprising a handful of basic axioms, the comprehension scheme, and the second-order induction axiom (in your first mathoverflow link, this is called Z_2): https://en.wikipedia.org/wiki/Second-order_arithmetic#The_fu... An other equivalent option would be to use the language…
You know more than me on logic so I defer to your expertise. https://math.stackexchange.com/questions/4753432/g%C3%B6dels... Andreas Blass in the comments says that the Incompleteness results don’t apply to the second order Axioms (tabling about PA_2 here and not Z_2) and that the second order axioms are not computably enumerable. Maybe that’s the correct concept I was remembering from mathematical logic class. Don’t…
He says that true sentences in second order logic aren't computably enumerable, he's not talking about the axioms.
> Don’t know if computably enumerable is the same as recursively enumerable
I've only ever seen them used as synonyms.
> Collect all true statements in this model of PA_2. Call that Super PA. That’s now my axiomatic system. I now have an axiomatic system that proves all true statements of arithmetic. Surely this set of axioms is not recursively enumerable.
What you call "Super PA" is called "the theory of PA". Its axioms are indeed not computably enumerable. That doesn't mean that the axioms of PA themselves aren't computably enumerable. And this much is true both for first and second order logic.
(edit: in fact, the set of Peano axioms isn't just computably enumerable, it's decidable - otherwise, it would be impossible to decide whether a proof is valid. This is at least true for FOL, but I do think it's also valid for SOL)