Earlier quoted context omitted.
> But I would go with something more like: tensors are a way to represent vectors so that the representation of a given vector is the same no matter what basis (or coordinate system) you choose for your vector space. That's just incorrect though for a couple of reasons. Firstly, a vector in the sense in which it is used in physics is a rank 1 tensor so it has this transformation behaviour just like other higher order…
> That's just incorrect though Quite possible. But that's in no small measure because I have yet to find an actual cogent definition of "tensor" that distinguishes a tensor from an array. (I have a similar problem with monads.) > So what I mean when I talk about the reality of the tensor I mean whatever it is the tensor is expressing in the physical universe OK, but then "the reality of a tensor" not depending on the…
What is a manifold?
131–138 of 138 posts
Re: What is a manifold?
#132Earlier quoted context omitted.
> That's just incorrect though Quite possible. But that's in no small measure because I have yet to find an actual cogent definition of "tensor" that distinguishes a tensor from an array. (I have a similar problem with monads.) > So what I mean when I talk about the reality of the tensor I mean whatever it is the tensor is expressing in the physical universe OK, but then "the reality of a tensor" not depending on the…
Could you elaborate on your problem with monads?
Re: What is a manifold?
#133Earlier quoted context omitted.
> You might find it circular reasoning but it is not Um, yes it is. "A foo is an object that transforms as a foo" is a circular definition because it refers to the thing being defined in the definition. That is what "circular definition" means .
Of course, there are some definitions that reference themselves that are not circular, or alternatively, some circular definitions that are useful. For example, the definition of "ancestors" might be "your parents and your parents' ancestors" (with the implication that if you don't exist, you don't have any ancestors). But I agree that this is not a useful definition for "tensor".
That's recursive, not circular. These are not the same thing despite being closely related. Recursive definitions are useful. Circular ones are not.
Re: What is a manifold?
#134Earlier quoted context omitted.
Of course, there are some definitions that reference themselves that are not circular, or alternatively, some circular definitions that are useful. For example, the definition of "ancestors" might be "your parents and your parents' ancestors" (with the implication that if you don't exist, you don't have any ancestors). But I agree that this is not a useful definition for "tensor".
> "your parents and your parents' ancestors" That's recursive, not circular. These are not the same thing despite being closely related. Recursive definitions are useful. Circular ones are not.
Re: What is a manifold?
#135Earlier quoted context omitted.
Could you elaborate on your problem with monads?
I don't understand them. None of the introductory materials I've read on them ever made any sense to me. I kinda sorta understand "state" and "maybe" but the general idea that links these two things together and (I am given to understand) leads to other cool stuff just eludes me.
Re: What is a manifold?
#136Earlier quoted context omitted.
> "your parents and your parents' ancestors" That's recursive, not circular. These are not the same thing despite being closely related. Recursive definitions are useful. Circular ones are not.
I was using the definition you gave for “circular”
Re: What is a manifold?
#137Earlier quoted context omitted.
> you can put a cd shaped object on You're thinking of open sets.
In particular, consider two intersecting planes. You can put all the discs you like on that surface, but it's not a manifold because on the line of intersection it's not locally R2.
Re: What is a manifold?
#138A manifold is a surface that you can put a cd shaped object on in any place on the surface, you can change the radius of the cd but it has to have some radius above 0.
Including the hole at the center of the CD?