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What is the inverse of a vector?

mattferraro.dev

101–110 of 198 posts

Re: What is the inverse of a vector?

#101
post #50

The writing is cute and the animations are nice, but none of it makes any sense. I stopped reading at > It is important to remember that bivectors have a certain redundancy built into them in the sense that s a ⃗ ∧ b ⃗ = a ⃗ ∧ s b ⃗ s a ∧ b = a ∧s b . We can write them using 6 numbers or 3 numbers, but they actually convey 5 degrees of freedom. Three (real) numbers have three degrees of freedom, by definition. (And n…

He's not talking about the triplet or sextet, he means that a bivector has 5 degrees of freedom.

That isn't correct either though, the basis consists of three unit bivectors, so they have at most 3 degrees of freedom.

Re: What is the inverse of a vector?

#104
post #30

Earlier quoted context omitted.

Damn. They don't teach these stuff here atleast not in a computer science curriculum. What degree did you learn? Iss this generally taught in all German engineering courses?

German and french engineering school are pretty rough on math theory, for the better or the worse. Mostly because a lot of theory was born in these two countries.

[deleted]

Re: What is the inverse of a vector?

#105
post #89
post #43

Earlier quoted context omitted.

Do you have an example of "Russian style explanation"?

Consider Kolmogorov’s entire Foundations of the Theory of Probability is 71 pages long [1]. [1] https://archive.org/details/foundationsofthe00kolm

... and that he revolutionised the understanding of turbulence in [1] which is four pages long.

[1] The local structure of turbulence in incompressible viscous fluids at very large Reynolds numbers, Dokl. Akad. Nauk. SSSR 30, 299-303. Reprinted in Proc. R. Soc. London A434, 9-13 (1991).

Re: What is the inverse of a vector?

#106
post #30

Earlier quoted context omitted.

Damn. They don't teach these stuff here atleast not in a computer science curriculum. What degree did you learn? Iss this generally taught in all German engineering courses?

German and french engineering school are pretty rough on math theory, for the better or the worse. Mostly because a lot of theory was born in these two countries.

[deleted]

Re: What is the inverse of a vector?

#108
post #78
post #58

Earlier quoted context omitted.

Yes, only three. As defined, two bivectors are equal if their areas are equal and if their oriented planes are equal. Therefore two more degrees of freedom are absorbed by taking rotations of the two vectors in the plane.Along with the rescaling the author noted, we're down to three from six.

That makes complete sense to me. But then later on they say "The output is a Geometric with a scalar component s and a bivector component ⇒c, which has 1 + 5 = 6 degrees of freedom so this system is not lossy! It should permit an unambiguous inversion operation!" If a bivector only has 3 degrees of freedom then the total is 4, which seems like it would be lossy?

I was also wondering this. But note that x^y is always perpendicular to x, so really only has two degrees of freedom while you need three to recover y (knowing x). Add in the dot product part to make up for it.

Re: What is the inverse of a vector?

#109
post #54

Earlier quoted context omitted.

> Not much maths in engineering/CS in germany either. That's simply not true. It depends entirely on the particular institution and its roots. There are two origins of CS in German universities: electrical engineering and maths. At universities where CS originated as a subfield of maths, undergrad CS education is very similar to a maths undergrad to the point that most of the tests/mid-terms are basically identical b…

> There are two origins of CS in German universities: electrical engineering and maths. Ah, I see, thanks for the information. Which university would be an example for the latter?

Seriously, which German university (not "FH") doesn't teach analysis and linear algebra in the first terms? I am really wondering.

Re: What is the inverse of a vector?

#110
post #86

Earlier quoted context omitted.

> Geometric algebra is, as the article points out, a more powerful version of the usual vector notation > the stuff that's already taught is better These two statements seem contradictory. > But it is deficient in various ways when compared to tensor notation (for calculations) and differential forms (e.g. if you want to work basis-free) The author made no claims about tensor notation or differential forms; perhaps t…

spekcular is correct. One could draw the following graph very roughly capturing how these concepts developed: Grassman’s exterior algebra -> Differential forms Cartan’s Exterior Derivatives -> Differential forms Quaternions -> Clifford Algebra exterior algebra -> Clifford Algebra -> geometric algebra Differential forms are a particular kind of tensor and tensors can be defined in terms of multilinear maps. As spekcul…

> As spekcular says, the standard curriculum covers differential forms, tensors and vectors... making geometric algebra a relatively small delta to pick up.

Could you be a bit more specific about which "standard curriculum"/"standard approach" you're talking about?

For example, in my formal education (high school; masters with physics major, comp. sci. minor; 4 years of a comp. sci. PhD (abandoned)), I did not encounter differential forms, tensors, multivectors, the wedge product or multilinear algebra (or quaternions, lie derivatives, differential geometry, (co)homology, etc.).

Maybe you're talking about a "standard approach" for a pure mathematics curriculum, or perhaps physics/math grad school?

All I can say is that high school and undergraduate physics (in the UK, circa the late naughties) (a) does not standardise on those topics, (b) is filled with tricky operations which are easy to mix up or perform the wrong way around (e.g. cross products, matrix multiplication, pseudovectors), and (c) many of those annoyances would simplify-away under GA.

It's a cliche that physicists (certainly when teaching) cherry-pick the parts of mathematics they find useful. All of those concepts would certainly be useful in a physics course, but would perhaps be too much to fit in; yet there's certainly enough scope to cherry-pick GA (since we can drop Gibbs-style vector algebra[0] to make room). Perhaps something else, like differential forms, might be even better; I honestly don't know (maybe I'll do some reading about it).

[0] By "Gibbs-style" I mean the 'cross product and dot product ought to be enough for anyone' approach that permeated my undergraduate learning.

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