http://i.gyazo.com/61d02988bb765bd95e26e48b576e8aaf.png This is the first 2048 variant that I'm able to beat. yay me... .__.
8402: 2048 from the other side
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Re: 8402: 2048 from the other side
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#15Earlier quoted context omitted.
the 3d one I found to be the easiest: http://joppi.github.io/2048-3D/ but 4d is terribly hard: http://huonw.github.io/2048-4D/ edit: I did a 3d victory in the 18 minutes in editing the comment. You can generally just push higher numbers into a corner, and pick either the left or the right side to consistently fold to and you'll get it mostly without thinking.
I find 4D much, much easier to control and visualize than 3D. Maybe if 3D was somehow presented in three dimensions I'd have an easier time of it, but the 4D one was easier to grok. That probably says something about how humans relate to interfaces that map higher dimensions to 2D planes, or maybe it's just the way the 4D layout maps to the screen.
I'm sure some people can maintain clear mental models of higher order dimensions and seamlessly translate the grids on the screen in some hyperspace in the mind.
But I, my friend, have no chance of that. The more I ignore that notion, the easier it becomes.
Re: 8402: 2048 from the other side
#16I finally beat it. This seems harder than 2048 since with 2048 a simple strategy can do well, where as with this game I had to search through more opponent AI moves. Is there a simple strategy for 8402?
Re: 8402: 2048 from the other side
#17Re: 8402: 2048 from the other side
#18I finally beat it. This seems harder than 2048 since with 2048 a simple strategy can do well, where as with this game I had to search through more opponent AI moves. Is there a simple strategy for 8402?
If you give the computer primarily 4's, you can clog the board by placing 2's where it cannot merge them. I beat the game on my first attempt this way.
Re: 8402: 2048 from the other side
#19My strategy was to give the AI a single 2 at the beginning, then only 4s. When the board fills up enough, there will probably be a space where you can put a second 2 to make it lose before it can combine them.