World Clicking Championship TheElevatorGame.com (and experiment) • Hacker News Board

kaerast wrote: post #5

So I'm guessing the experiment is either A/B testing of layouts of number pads, or it's testing to see if people can cheat the leaderboard. Also, it must be a slow news day for this to get to front page.

Yes, it seems to be A/B (or maybe multivariant) testing. Tried the site through hidemyass.com and got the numbers running in bottom-top order while loading it directly I got top-bottom order. I hope the creator will publish the results when finished :).

Re: World Clicking Championship TheElevatorGame.com (and experiment)

#18

Post by jhherren » Wed, Feb 01, 2012, 1:48 AM UTC

joshwprinceton wrote: post #16

jhherren wrote: post #12

$('.pickme').click()

is there a way I could have disabled that?

Of course. Give the numbers a randomly generated id, and check for the winning value server side. You'd also want display the numbers in a way where it's tougher to compare them than checking the text values--the target value is $('#left h1').text().trim(). So that means using images (not named 1.jpg!) or canvas or something like that.

Also, your app is vulnerable to replay. I can keep POSTing the same request over and over and my score increases.

Re: World Clicking Championship TheElevatorGame.com (and experiment)

#19

Post by openyogurt » Thu, Feb 02, 2012, 2:06 PM UTC

jhherren wrote: post #18

joshwprinceton wrote: post #16

Earlier quoted context omitted.

is there a way I could have disabled that?

Of course. Give the numbers a randomly generated id, and check for the winning value server side. You'd also want display the numbers in a way where it's tougher to compare them than checking the text values--the target value is $('#left h1').text().trim(). So that means using images (not named 1.jpg!) or canvas or something like that. Also, your app is vulnerable to replay. I can keep POSTing the same request over a…

As it is now, you don't even need to match the numbers. Just find the form and submit it. $("#right form").submit()