Player 1: Roll a 3, 5, 6, 8, 9, 11 or 12. Don't purchase, so it goes to auction. In auction player 2 buys for 100% of their cash.
Player 2: Rolls a 4, lands on income tax. Game over.
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Player 1: Roll a 3, 5, 6, 8, 9, 11 or 12. Don't purchase, so it goes to auction. In auction player 2 buys for 100% of their cash.
Player 2: Rolls a 4, lands on income tax. Game over.
Anyone want to roughly calculate the odds of this actually happening?
The specific sequence of rolls has 5 doubles (which can only occur one way) and 4 unequal pairs (which can occur two ways). Each double has a 1/36 chance of happening while the unequal pairs have a 1/18 chance. So that's 1/36^5 * 1/18^4 = 1/6,347,497,291,776 or about 1.5 times ten to the minus thirteen. It's interesting that the last four digits of the denominator of the probability of the shortest game of Monopoly a…
Anyone want to roughly calculate the odds of this actually happening?
The specific sequence of rolls has 5 doubles (which can only occur one way) and 4 unequal pairs (which can occur two ways). Each double has a 1/36 chance of happening while the unequal pairs have a 1/18 chance. So that's 1/36^5 * 1/18^4 = 1/6,347,497,291,776 or about 1.5 times ten to the minus thirteen. It's interesting that the last four digits of the denominator of the probability of the shortest game of Monopoly a…
Anyone want to roughly calculate the odds of this actually happening?
0 in practice, who decides to buy nothing? And even if player one declines to buy, player two can buy it via the auction.
A game like this can even go fast paced where the next player is making their turn while you're still interacting with the bank from your turn, while someone else is calculating interest.
Doesn't sound fun typing it out but it was a blast.
If you drop some presumptions about the players you can go even faster-- Player 1: Roll a 3, 5, 6, 8, 9, 11 or 12. Don't purchase, so it goes to auction. In auction player 2 buys for 100% of their cash. Player 2: Rolls a 4, lands on income tax. Game over.
Neat. The longest possible game is playing with family that don’t like or don’t know the rules and like to put money on free parking.
That's when you sneeze or find some other reason to bump the table hard enough to lose the places of all of the pieces. "Ooops, I guess we'll have to pick this game up later"
“Huh? I thought that’s what this game was about. Y’all started it with that Free Parking nonsense.”
Anyone want to roughly calculate the odds of this actually happening?
If you drop some presumptions about the players you can go even faster-- Player 1: Roll a 3, 5, 6, 8, 9, 11 or 12. Don't purchase, so it goes to auction. In auction player 2 buys for 100% of their cash. Player 2: Rolls a 4, lands on income tax. Game over.
The probability for executing this strategy is: P(3)+P(5)+P(6)+P(8)+P(9)+P(11)+P(12) * P(4).
Plug in the numbers from https://statweb.stanford.edu/~susan/courses/s60/split/node65...
(0.0556+0.1111+0.1389+0.1389+0.1111+0.0556+0.278)*0.0833 = 0.07407036
So 7.4%.
Earlier quoted context omitted.
The specific sequence of rolls has 5 doubles (which can only occur one way) and 4 unequal pairs (which can occur two ways). Each double has a 1/36 chance of happening while the unequal pairs have a 1/18 chance. So that's 1/36^5 * 1/18^4 = 1/6,347,497,291,776 or about 1.5 times ten to the minus thirteen. It's interesting that the last four digits of the denominator of the probability of the shortest game of Monopoly a…
And don’t forget that Player 2 most also pick an “advance to Boardwalk” card out of a shuffled deck.