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What are unevaluated operands in C++?

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Re: What are unevaluated operands in C++?

#11
post #8

Earlier quoted context omitted.

> #define MY_ASSERT(expr) sizeof(expr) sizeof accepts a type or an expression as its input, so it would compile successfully if expr were a type but not a valid expression (say, int).

You could do sizeof((expr)?1:2) instead, which would also force expr to be contextually convertible to a bool.

sizeof((expr)) would suffice to filter out types.

Re: What are unevaluated operands in C++?

#12
If you don’t know what SFINAE is (the article uses the acronym a lot but doesn’t define it):

> Substitution failure is not an error (SFINAE) refers to a situation in C++ where an invalid substitution of template parameters is not in itself an error.

https://en.m.wikipedia.org/wiki/Substitution_failure_is_not_...

Re: What are unevaluated operands in C++?

#13
post #12

If you don’t know what SFINAE is (the article uses the acronym a lot but doesn’t define it): > Substitution failure is not an error (SFINAE) refers to a situation in C++ where an invalid substitution of template parameters is not in itself an error. https://en.m.wikipedia.org/wiki/Substitution_failure_is_not_...

This is a intermediate-level technique that's quite commonly used. Take a look at to find out what you can do with it! Specifically you can use std::enable_if in a return type or template parameter to conditionally enable an overload.

Re: What are unevaluated operands in C++?

#14
Small typo near start:

> Up to C++17, there are four operators the operands of which are unevaluated: typeof, sizeof, decltype, and noexcept.

"typeof" should be "typeid". This confused me a bit as I thought the article was going to talk about a nonstandard predecessor to decltype.

The article was interesting, but its contents didn't really match it's title. It's not about unevaluated operands in general but just their use in SFINAE specifically. For example, sizeof is dismissed as not much use for SFINAE, which is true but it certainly has a lot of other uses! And if you read this article having not seen decltype before, I think you'd get the wrong impression about its range of uses.

Re: What are unevaluated operands in C++?

#15
post #7

This seems like a potential solution to the problem of how to #define MY_ASSERT(x) in release mode such that it fails to compile if "x" is not a valid expression. Previous I have used this idiom: #define MY_ASSERT(expr) do {} while (false && (expr)) Another possible alternative might be: #define MY_ASSERT(expr) sizeof(expr)

Note that lambda expressions are not allowed in an unevaluated context. What about this?

   #define MY_ASSERT(expr) do {} while (false && ((expr), false))
This doesn't require expr to be convertible to bool.

Re: What are unevaluated operands in C++?

#16

Small typo near start: > Up to C++17, there are four operators the operands of which are unevaluated: typeof, sizeof, decltype, and noexcept. "typeof" should be "typeid". This confused me a bit as I thought the article was going to talk about a nonstandard predecessor to decltype. The article was interesting, but its contents didn't really match it's title. It's not about unevaluated operands in general but just thei…

confusingly typeid can evaluate its expression parameter, if the expression type is polymorphic as the correct type info would be a runtime property (in fact I thought that typeid would always evaluate its parameters, but apparently that's not the case).

Re: What are unevaluated operands in C++?

#18

I'm a c++ programmer but honestly hate the language more and more with every year, because it's so complex. Can somebody explain the first code sample to me?

I agree. I really liked C++11, it seemed to be a big improvement to the language, but ever since then, its just been getting more and more complex to the point where I no longer feel like I can understand the language at all anymore.

Re: What are unevaluated operands in C++?

#19
post #15
post #7

This seems like a potential solution to the problem of how to #define MY_ASSERT(x) in release mode such that it fails to compile if "x" is not a valid expression. Previous I have used this idiom: #define MY_ASSERT(expr) do {} while (false && (expr)) Another possible alternative might be: #define MY_ASSERT(expr) sizeof(expr)

Note that lambda expressions are not allowed in an unevaluated context. What about this? #define MY_ASSERT(expr) do {} while (false && ((expr), false)) This doesn't require expr to be convertible to bool .

Actually, the argument of MY_ASSERT should always be convertible to bool, even in release mode.

Re: What are unevaluated operands in C++?

#20
post #7

This seems like a potential solution to the problem of how to #define MY_ASSERT(x) in release mode such that it fails to compile if "x" is not a valid expression. Previous I have used this idiom: #define MY_ASSERT(expr) do {} while (false && (expr)) Another possible alternative might be: #define MY_ASSERT(expr) sizeof(expr)

Why not just

    #define MY_ASSERT(expr) ((void)(false && (expr)))
The problem the do-while idiom is that the macro result is not an expression, so it can’t be used in certain cases.
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