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Storing Renewable Energy Using Thermodynamics

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Re: Storing Renewable Energy Using Thermodynamics

#11
post #10

Assuming about 300K ambient temperature (on site, above ground), 800K working temperature (store the heat at 500°C) and that the second law of thermodynamics still holds, the roundtrip efficiency can not be 70%. It must be below 40%, and not just a bit below.

I don't follow. The second law of thermodynamics doesn't say anything about the specific efficiency limits of an energy conversion or storage system. Ideal reversible systems can maintain entropy if fully isolated (e.g. insulated). In real systems, perfect isolation is impractical, of course, but the resulting loss of energy is a function of the shortomings of the manufacturers of the system (e.g. use of low R factor insulation, high resistance electrical conductors, or poorly shaped pump impellers, etc), not some simple "2nd law limit".

Re: Storing Renewable Energy Using Thermodynamics

#12
post #8
post #5

They claim 0.05€ (~0.06USD) per KWh lifetime cost. Anybody know how that compares to current prices of grid-scale batteries? I can't find a up-to-date source.

Pumped hydro is about 3x as expensive, and batteries I think are still more expensive than pumped hydro, so it's absurdly cheap.

Pumped hydro and flywheels are at least demonstrated cost effective solutions. This? They don't even provide any details.

Re: Storing Renewable Energy Using Thermodynamics

#13
post #10

Assuming about 300K ambient temperature (on site, above ground), 800K working temperature (store the heat at 500°C) and that the second law of thermodynamics still holds, the roundtrip efficiency can not be 70%. It must be below 40%, and not just a bit below.

I don't follow. The second law of thermodynamics doesn't say anything about the specific efficiency limits of an energy conversion or storage system. Ideal reversible systems can maintain entropy if fully isolated (e.g. insulated). In real systems, perfect isolation is impractical, of course, but the resulting loss of energy is a function of the shortomings of the manufacturers of the system (e.g. use of low R factor…

https://en.wikipedia.org/wiki/Carnot%27s_theorem_(thermodyna...

Re: Storing Renewable Energy Using Thermodynamics

#15

Earlier quoted context omitted.

I don't follow. The second law of thermodynamics doesn't say anything about the specific efficiency limits of an energy conversion or storage system. Ideal reversible systems can maintain entropy if fully isolated (e.g. insulated). In real systems, perfect isolation is impractical, of course, but the resulting loss of energy is a function of the shortomings of the manufacturers of the system (e.g. use of low R factor…

https://en.wikipedia.org/wiki/Carnot%27s_theorem_(thermodyna...

Heat->mechanical energy can only be (1-Tc/Th) efficient. But mechanical energy->heat can be 1/(1-Tc/Th) efficient, so you can get close to unity round trip efficiency.

That's why people use heat pumps to heat buildings, because you get more heat out than energy in (the extra heat comes from the ground).

Re: Storing Renewable Energy Using Thermodynamics

#17
post #15

Earlier quoted context omitted.

https://en.wikipedia.org/wiki/Carnot%27s_theorem_(thermodyna...

Heat->mechanical energy can only be (1-Tc/Th) efficient. But mechanical energy->heat can be 1/(1-Tc/Th) efficient, so you can get close to unity round trip efficiency. That's why people use heat pumps to heat buildings, because you get more heat out than energy in (the extra heat comes from the ground).

I need further explanation before this makes sense to me. How can M->H have greater than 100% efficiency?

You mentioned getting heat from the ground, but that only happens when the ground heat is greater than T_h, right? At which point it just sounds like geothermal but with extra steps.

Re: Storing Renewable Energy Using Thermodynamics

#18
post #10

Assuming about 300K ambient temperature (on site, above ground), 800K working temperature (store the heat at 500°C) and that the second law of thermodynamics still holds, the roundtrip efficiency can not be 70%. It must be below 40%, and not just a bit below.

I think you might be wrong but my thermal is very rusty. Where you are wrong is that you might be forgetting the over 100% efficiency in heat transfer when using a heat pump.

http://energystorage.org/energy-storage/technologies/pumped-...

https://www.economist.com/news/technology-quarterly/21603184...

http://wordpress.ei.columbia.edu/lenfest/files/2012/11/Abstr...

Re: Storing Renewable Energy Using Thermodynamics

#20
post #17
post #15

Earlier quoted context omitted.

Heat->mechanical energy can only be (1-Tc/Th) efficient. But mechanical energy->heat can be 1/(1-Tc/Th) efficient, so you can get close to unity round trip efficiency. That's why people use heat pumps to heat buildings, because you get more heat out than energy in (the extra heat comes from the ground).

I need further explanation before this makes sense to me. How can M->H have greater than 100% efficiency? You mentioned getting heat from the ground, but that only happens when the ground heat is greater than T_h, right? At which point it just sounds like geothermal but with extra steps.

A heat pump transfers heat from the cold side to the hot side, making the hot side hotter and the cold side colder. The thing you're heating is at Th and ground is at Tc. By putting 1 J of mechanical work in, you might draw 3 J from the cold side and pump 4 J into the hot side.
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