11–20 of 20 posts
Earlier quoted context omitted.
You can create more arrangements if you treat the bridge like two pieces, which it is.
How so? If your goal is to create a loop, the two pieces must be joined together.
I suppose it will have to be a big box, mathematically.
Well that makes my "how many ways can I arrange an Ikea train set" look pretty lame. http://blog.jgc.org/2010/01/more-fun-with-toys-ikea-lillabo-...
I've always wanted to make a sorting box that, given any quantity of random Lego Mindstorms parts, sorts the parts into shape/size/purpose bins. A static box, no moving parts but the raw feed. I suppose it will have to be a big box, mathematically.
Some of these are interesting.
I'd be interested to see how good something that sorted purely by weight could be. And then with a vision stage?
Well that makes my "how many ways can I arrange an Ikea train set" look pretty lame. http://blog.jgc.org/2010/01/more-fun-with-toys-ikea-lillabo-...
Earlier quoted context omitted.
How so? If your goal is to create a loop, the two pieces must be joined together.
You could lengthen the bridge (theoretically, the pieces might not fit that snug) with any combination of the pieces all the way down to the case of a reverse bridge connected at the bottom.
Earlier quoted context omitted.
You could lengthen the bridge (theoretically, the pieces might not fit that snug) with any combination of the pieces all the way down to the case of a reverse bridge connected at the bottom.
Unless they fit very snugly, I don't think anything would hold up the extra pieces in the middle, especially not well enough to support a train.
[0] http://i.ebayimg.com/00/s/MTIwMFgxNjAw/z/DAUAAOSwGvhT3ny3/$_...
Earlier quoted context omitted.
Unless they fit very snugly, I don't think anything would hold up the extra pieces in the middle, especially not well enough to support a train.
The original creator of this type of train track offers just such a support piece.[0] You can also 3D print your own supports![1] [0] http://i.ebayimg.com/00/s/MTIwMFgxNjAw/z/DAUAAOSwGvhT3ny3/$_... [1] http://www.thingiverse.com/thing:110221
Won't their definition conflict with the rectilinear definition? Specifically, there are distinct rectilinear configurations which are homotopic. With two bricks connected by at corner, there are two rectilinear configurations but both are homotopic. So their method used to count "homotopy equivalence classes which contain at least one rectilinear configuration" would yield a lower number than the previous result. Th…
Where are you getting two from? By the definitions on this page, it seems to me like there are four corner-connected rectilinear configurations of two bricks, and also four homotopy equivalence classes, so there's no inconsistency. +--+ +--+ | | | | | | | | | |-+ +-| | +--+ | | +--+ | | | | | | | | +--+ +--+ +-----+ +-----+ | |-+ +-| | +-----+ | | +-----+ | | | | | | | | +--+ +--+
