Is this available on Android?
Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
131–139 of 139 posts
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#132I just got the username "James". This never happens. If you can solve the "AB—BC" problem, then you'll have a really powerful application that'll easily get some investments, you just need to market it right.
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#133Sorry, not going to happen :)
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#134I just got the username "James". This never happens. If you can solve the "AB—BC" problem, then you'll have a really powerful application that'll easily get some investments, you just need to market it right.
what's the AB-BC problem?
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#135I'm curious about how this actually works, geometrically. Example: A B C Those are three people. Imagine each segment is 1 mile long. So A can see B; B can see C; but A can't see C. If B and C are having a conversation, does A see B talking to someone who effectively does not exist?
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#136Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#137Great idea, nobody in my area yet so I cannot check the execution. (Barcelona, Europe) Please, don't let this become something bad as happened with ChatRoulette when it became viral.
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#138- Push notifications are much needed.
- I logged out, but now I can't log back in.
- I'm unable to send more than one message at a time, but it's complaining that I need to wait 2 seconds.
Re: Show HN: Popcorn Messaging – Anonymously chat with people within 1 mile
#139I'm curious about how this actually works, geometrically. Example: A B C Those are three people. Imagine each segment is 1 mile long. So A can see B; B can see C; but A can't see C. If B and C are having a conversation, does A see B talking to someone who effectively does not exist?
turns out you're right. anybody have suggestions on how to fix this?