Ask HN: Why do some YC companies keep posting the same job bi-weekly?

Post by [deleted] » Mon, Jan 15, 2024, 10:53 PM UTC

bombcar wrote: post #10

dang wrote: post #8

I assume you're talking about the front-page job ads described in https://news.ycombinator.com/newsfaq.html and https://news.ycombinator.com/jobguide.html ? I've been meaning to look at the data to see what needs to be tightened or cleaned up there. Currently the rule is that active YC companies can have an ad at most once per two weeks (as you saw), with the caveat that priority is always given to the company that h…

I just hope someday they find that engineer! They've been looking for him for years. Maybe they should be required to re-word it once a month or once every 6 months. After awhile I start to be put off by the company's name just because of the perpetual noticing.

Post by brailsafe » Mon, Jan 15, 2024, 11:40 PM UTC

zeitgeistcowboy wrote: post #31

I just talked with a recruiter that said 80% of companies are posting jobs just so they collect the answers to the diversity questions so they can prove to the government that they are considering everyone. You know, the questions about race, gender, veteran status, and disabilities.

Post by gabrielsroka » Tue, Jan 16, 2024, 12:44 AM UTC

conductr wrote: post #12

Easy Post is the one I’ve seen constantly and consistently over several years. I assume it’s a growth hack where they just constantly have their name in front of HN eyeballs

  # Using https://gabrielsroka.github.io/webpages/pith.html
  
  u = '//hn.algolia.com/api/v1/search_by_date?tags=job'
  jobs = []
  for p in range(50)
    ? 'Fetching page', p
    s = await getJson(u + '&page=' + p)
    s.hits.forEach(j => j.name = j.title.match(/(.*?) \(/)?.[1] ?? j.title)
    jobs = jobs.concat(s.hits)
  debug.clear()
  jobs.sort((j1, j2) => (j1.name + j1.created_at).localeCompare(j2.name + j2.created_at))
  ? jobs.map(j => j.created_at + ': ' + j.name).join('\n')
  
  v = jobs.map(j => j.name).reduce((o, n) => (o[n] = o[n] + 1 || 1, o), {})
  v = Object.entries(v).sort((v1, v2) => v2[1] - v1[1])
  
  | Name | Count
  for [n, c] in v
    + n >> c

Post by pcthrowaway » Tue, Jan 16, 2024, 4:06 PM UTC

bb88 wrote: post #21

bombcar wrote: post #10

Earlier quoted context omitted.

I just hope someday they find that engineer! They've been looking for him for years. Maybe they should be required to re-word it once a month or once every 6 months. After awhile I start to be put off by the company's name just because of the perpetual noticing.

There's a management strategy to always interview even if they don't actually need anyone. The idea is that if someone spectacular comes on the market they can either replace an existing dev, or create a new role for that person.

Post by solardev » Wed, Jan 17, 2024, 12:32 PM UTC

Tommah wrote: post #26

sk11001 wrote: post #7

Earlier quoted context omitted.

"Hmm Meticulous have been looking for a #3 founding engineer for 18 months, they're sooo dynamic"

Maybe they've hired 18 people and each one has only lasted a month! It doesn't get much more dynamic than that.