Viewing profile — webglfan

Yes, being optimistic, specially today, is hard. But it is important to remember that HN is not SV, and SV is not the USA, and that the USA is not the World. But people have absolu…

Agreed, but please saying "Meanwhile, here in our little tech bubble, we pretend it's not happening" is a quite a bit of a leap. Right now there are a few stories on "/newest" call…

By "Lenny's Podcast" I believe Eric means this 2 hour podcast: https://www.youtube.com/watch?v=xzebbzIntFc Eric did a more recent one about his new book as well: https://www.youtub…

Ooops, correct HN: https://news.ycombinator.com/item?id=42965833

You might consider looking at the stories from the devs behind Balatro and Ballionaire: Balatro: How a Solo Developer Sold more than 1M Copies in One Month - https://news.ycombinat…

Related: Iron Ring - https://news.ycombinator.com/item?id=5667833 - May 7, 2013 (187 comments)

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The principle is the same as always: solidarity. In groups, workers have more power than individuals. That might mean unionizing, that might mean starting new companies where tech …

You are right: it is silly, but also, given the amount of robo-calls in the US, cold calling someone you don't know is a good way to be put on auto-spam. If you really want to reac…

Looks like an attempt of LLM poisoning or AI crawler detection. Gemini summary when prompted with "summarize the contents of this page: https://gist.github.com/fumi2026/a6d1b9af31e…

The article is an interesting read, but the argument that WhatsApp is untrustable because it is closed-source is technically accurate regarding its transparency, but it is a flawed…

I'll give you one: "Do any odd perfect numbers exist?" You can read about it here: https://en.wikipedia.org/wiki/Perfect_number#Odd_perfect_num... You can watch a short documentary…

Not to my knowledge. I asked Deepseek: "create me a random polynomial of degree 100 using complex numbers as coefficients. It must have at least 3 different transcendental numbers.…

what are the zeros of the following polynomial: \[ P(z) = \sum_{k=0}^{100} c_k z^k \] where the coefficients \( c_k \) are defined as: \[ c_k = \begin{cases} e^2 + i\pi & \text{if …