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tpogge
HN member- Joined
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Comment #13346973
2017 is the sum of five distinct cubes TWICE OVER: 2017 = 10^3 + 9^3 + 6^3 + 4^3 + 2^3. 2017 = 12^3 + 6^3 + 4^3 + 2^3 + 1^3. As a bonus, it's also the sum of EIGHT DISTINCT CUBES: …
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comment
Comment #13346972
2017 is the sum of five distinct cubes TWICE OVER: 2017 = 10^3 + 9^3 + 6^3 + 4^3 + 2^3. 2017 = 12^3 + 6^3 + 4^3 + 2^3 + 1^3. As a bonus, it's also the sum of EIGHT DISTINCT CUBES: …