Viewing profile — siegelzero

Very cool! There's definitely some similarity to Ramanujan Sums, though the approach here sort of packages the fizz-buzz divisibility properties into one function. https://en.wikip…

Yes you're right it's typically stated as "shaves all those, and those only, who do not..." https://en.wikipedia.org/wiki/Barber_paradox

I can recommend the book Guide to Graph Colouring: Algorithms and Applications by Lewis. It covers techniques including some state of the art methods for getting good but not prova…

"Irresistible Integrals: Symbolics, Analysis and Experiments in the Evaluation of Integrals" - Boros and Moll "Inside Interesting Integrals" - Nahin

https://archive.ph/39IUU

Did you mean this site? It has some pretty great content. https://musicforprogramming.net/one

https://web.archive.org/web/20220526162025/https://bartwrons...

His article about bit manipulation is very nice, as well. https://catonmat.net/low-level-bit-hacks

Penn State has a bunch of their graduate stats courses online [1]. I worked through some of their time series class [2] and found it to be pretty good quality. [1] https://online.s…

And those who want to see trees go to r/marijuanaenthusiasts

This paper was posted earlier with Anonymous authors: https://news.ycombinator.com/item?id=21084748

There are some closely related difficult problems. Consider the fraction a/b, and let r be the length of the repeating fractional part. Then r <= b - 1. Moreover, if r == b - 1, th…

Check out the (official?) site to buy Wheel of Fortune/Jeopardy! tickets for some nostalgia: http://www.wheeljeopardytickets.com/

I've solved 249 of them. I don't remember when I joined, but it must have been about 10 years ago. Solving PE problems was a great way to unwind in grad school (studying math) and …

Reminds me of bash roulette. http://www.bash.org/?96164

I was always fond of "presbyterians" "britneyspears".

Yeah, this proof seems to work. I was thinking of the case where you attack $e^2$ directly, instead of going after both $e$ and $e^{-1}$.

It's simply a habit from LaTeX :-)

This a very terse proof. It is stated "The same method can also be used to prove that e cannot be a root of a second degree equation with rational coefficients", but if I recall corr…

It's a contradiction because there are no integers strictly between 0 and 1.

That's not exactly true. Density arguments similar to this are fairly common in number theory (even if the arguments aren't rigorous). Granted, one has to be careful with arguments…

Ono is the most self-promoting mathematician I've ever seen. He's done some outstanding work, but he certainly enjoys the spotlight.

Most people currently studying for a Masters or PhD aren't "laymen".

Multi-section most likely means that there are several different sections of the same course running simultaneously. In addition, there are probably different professors teaching t…