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mxbr
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Comment #21376507
2 * (1..12).reduce(&:+) You could also use the closed summation formula: (n^2 + n) / 2. In our case that shortens to just 12*13=156.
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Comment #20029786
For Berlin, there is an interesting visualization of this question: https://verkehrsluecken.tagesspiegel.de/en/