Viewing profile — cruegge
cruegge
HN member- Joined
- Sun, Aug 14, 2016, 1:55 PM UTC
- HN karma
- 30
- Public activity
- 14 items
- HN profile
- View on Hacker News ↗
About cruegge
No profile information was provided.
Recent public activity
-
comment
Comment #47641337
Correct me if I'm wrong, but I don't think humans are reptiles, phylogenetically. The Synapsida (containing mammals) and Sauropsida (containing reptiles) are sibling groups inside …
-
comment
Comment #47287065
Probably Majutsu, https://github.com/0WD0/majutsu
-
comment
Comment #45763714
They're not infailable, though. For example, TeX's primitive for fractions is actually {a \over b}, LaTeX's \frac is a macro on top of that. The consequence is that while typesetti…
-
comment
Comment #42189726
I think a = sqrt(2), b = log(9)/log(2) with a^b = 3 is easier. To show that b is irrational, assume b = n/m for integer n, m. Then 9^m = 2^n, which can't be the case since the lhs …
-
comment
Comment #37729776
> Yes, I thought this was clear from my statement. Yeah, sorry, wasn't really necessary to repeat that point. I was too focused on the "limiting the height of the tree to 32" formu…
-
comment
Comment #37724118
It's not limited to 32, but afterwards search will be linear along child[0]. Using rotation would not make a difference, since you're in the collision case already, so you would ef…
-
comment
Comment #33419326
A more advanced example of mutual recursion: it's possible to perform an exhaustive search over the "Cantor space" of all infinite sequences of bits that either finds a sequence sa…
-
comment
Comment #32840898
Ok, the more I try to understand this, the more confused I get. Probably just scrap everything I said, I'll need to do some more reading.
-
comment
Comment #32837614
I see. Checking the formulation of the incompleteness theorem again, I noticed that I probably misunderstood something here: it indeed essentially requires proofs to be verifyable,…
-
comment
Comment #32835555
What I meant to say is that multiple models are not the only reason for something to be true but unprovable, the incompleteness theorem also holds in more general conditions. Conce…
-
comment
Comment #32834555
That's a good intuition for first order PA, where the completeness theorem holds, but not the full story either. PA in second order logic only has a single model, but is still inco…
-
comment
Comment #31491941
If found “TeX by Topic” a great introduction, it's less overwhelming than the TeX book. Also really helpful in wrapping your head around macro expansion is the `texdef` cli tool, w…
-
comment
Comment #25185761
It does double the residue, but modulo 19. 2 * 18 = 36 = 17 (mod 19) and 2 * 10 = 20 = 1 (mod 19). The reason is that the method consists essentially of two steps. (1) Subtract a s…
-
comment
Comment #18997304
They have an FAQ item concerning that: https://jmap.io/#why-is-it-not-rest-based ?